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I found this from a youtube video, and was wondering if there is a way to get them while they are still fixed, and of course that I have a way to edit them, before they fixed them.

A:

You can use the web-based version of VLC, and download the audio files from it.
The problem with the VLC in the case of the video samples you mentioned, is that the whole video is broken. If the audio is extracted from the video file and stored to a different file, it works fine.
Open VLC and go to Network. Right click on the file and select Open Network Stream. Select the one to the right of the “Play” link. Select Open network location. Select the one that says “Local files”.
Now you can right click on the original file and select Save As. Select a name for the new file, and move it into the folder where you would like to save it.

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I’m trying to replace them with a new list based on the index of the similar statement. Something like this:
SOME_VALUE=[10,20,30,40,50,90,0,2,100]
SOME_VALUE_NEW=[10,20,30,40,50,90]

After looking at this thread How to create a list of a list, I’ve come up with this following code:
from itertools import groupby, chain, izip
SOME_VALUE=[10,20,30,40,50,90,0,2,100]
SOME_VALUE_NEW=[]
for i, v in enumerate(SOME_VALUE):
for k, g in groupby(SOME_VALUE, key=lambda x: x == v):
SOME_VALUE_NEW.extend(chain.from_iterable(g))
SOME_VALUE_NEW[i] = [sum(s) for s in SOME_VALUE_NEW[i]]
print(SOME_VALUE_NEW)

The code fails to replace some of the values (90, and 0) with a value from the new list, and I can’t figure out why.

A:

I’m not sure why you’re using an enumerate() on the groupby.
This should work for you:
from itertools import groupby, izip
SOME_VALUE=[10,20,30,40,50,90,0,2,100]
SOME_VALUE_NEW=[]
for i, v in SOME_VALUE:
for k, g in groupby(SOME_VALUE, key=lambda x: x == v):
SOME_VALUE_NEW.extend(sum(s for s in chain.from_iterable(g)))
print(SOME_VALUE_NEW)

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